# The the balanced equations to: solutions of lithium sulfate and potassium phosphate are mixed together to make lithium phosphate

The the balanced equations to: solutions of lithium sulfate and potassium phosphate are mixed together to make lithium phosphate and potassium sulfate

amberchule9681

1. Cu(2+) [solution] + 2OH(-) [solution]= Cu(OH)↓ [solid]

2. 3CO3(2-) [solution] + 2Al(3+) [solution] + 3H2O [liquid] = 2Al(OH)3↓ [solid] + 3CO2↑ [gas]

2. 2PO4(3-) [solution] + 3Ba(2+) [solution] = Ba3(PO4)2↓ [solid]

gtsaeg409

The equations are given below.

Explanation:

To write the net ionic equations, we do not include spectator ions in the equations.

Spectator ions are defined as the ions which do not participate in a chemical reactions. These ions exists in the same form on both the sides of the reaction.

Equations for the given reactions is given as:

a.) Copper(II) sulfate, $CuSO_4$, and potassium hydroxide, KOH

Ionic equation follows:

$Cu^{2+}(aq.)+SO_4^{2-}(aq.)+2K^+(aq.)+2OH^-(aq.)\rightarrow Cu(OH)_2(s)+2K^+(aq.)+SO_4^{2-}(aq.)$

Removing the spectator ions, we get the net ionic equation, which is:

$Cu^{2+}(aq.)+2OH^-(aq.)\rightarrow Cu(OH)_2(s)$

b.)  Lithium carbonate, $Li_2CO_3$, and aluminum nitrate, $Al(NO_3)_3$

Ionic equation follows:

$6Li^+(aq.)+6CO_3^{2-}(aq.)+2Al^{3+}(aq.)+6NO_3^-(aq.)\rightarrow 6Li^+(aq.)+6NO_3^-(aq.)+Al_2(CO_3)_3(s)$

Removing the spectator ions, we get the net ionic equation, which is:

$6CO_3^{2-}(aq.)+2Al^{3+}(aq.)\rightarrow Al_2(CO_3)_3(s)$

c.) Sodium phosphate, $Na_3PO_4$, and barium chloride, $BaCl_2$

Ionic equation follows:

$6Na^+(aq.)+2PO_4^{3-}(aq.)+3Ba^{2+}(aq.)+6Cl^-(aq.)\rightarrow Ba_3(PO_4)_2(s)+6Na^+(aq.)+6Cl^-(aq.)$

Removing the spectator ions, we get the net ionic equation, which is:

$3Ba^{2+}(aq.)+2PO_4^{3-}(aq.)\rightarrow Ba_3(PO_4)_2(s)$

Hence, the equations are given above.

lol4373

$3Li_2SO_4+2K_3PO_4\rightarrow 2Li_3PO_4+3K_2SO_4$

Explanation:

Hello!

In this case, when lithium sulfate and potassium phosphate solutions are mixed to yield lithium phosphate and potassium sulfate, the following chemical equation comes up:

$Li_2SO_4+K_3PO_4\rightarrow Li_3PO_4+K_2SO_4$

However, as atoms are not balanced we apply the inspection method to obtain:

$3Li_2SO_4+2K_3PO_4\rightarrow 2Li_3PO_4+3K_2SO_4$

Best regards!

ssalusso1533

1. Cu(2+) [solution] + 2OH(-) [solution]= Cu(OH)↓ [solid]

2. 3CO3(2-) [solution] + 2Al(3+) [solution] + 3H2O [liquid] = 2Al(OH)3↓ [solid] + 3CO2↑ [gas]

2. 2PO4(3-) [solution] + 3Ba(2+) [solution] = Ba3(PO4)2↓ [solid]