# Should include inputs, processes, outputs, and feedback of a specific product/process/system. What are the intended and unintended outs for the product/process/system?

Should include inputs, processes, outputs, and feedback of a specific product/process/system. What are the intended and unintended outs for the product/process/system? Does the system use open- or closed-loop feedback? Explain. How does the product/process/system convert inputs into outputs? What other systems are directly dependent on your given system? What other systems are indirectly dependent on your given system?

majorsam82

A) promote cell elongation and cell division in stems.

jay5134

Open and close to control evaporation

LuluMathLover101

A. promote cell elongation and cell division in stems.

Explanation:

Auxins are the plant hormones, which are typically found in the shoot and root tips.  They promote cell division at the tip of roots and shoots as a result of this help in elongation of the stems and roots. They inhibit the growth of the lateral buds hence maintains apical dominance.

mckenziew6969

Auxins stimulate seed growth and fruit development...the answer is B.

brennarfa

See the attached figure.

Step-by-step explanation:

The given function is $f(x) = -11 \ cos(\frac{\pi x}{48} -\frac{5 \pi}{12} )+28$

We should know that:e

y = cos x

So, the maximum is y = 1 at x = 0 and the minimum is y = -1 at x = π

So, for the given function

The maximum of f(x) will be at $cos(\frac{\pi x}{48} -\frac{5 \pi}{12}) = -1$

And f(x) = -11 * -1 + 28 = 11 + 28 = 39

$cos(\frac{\pi x}{48} -\frac{5 \pi}{12}) = -1$

∴ $(\frac{\pi x}{48} -\frac{5 \pi}{12}) = \pi$

$\frac{\pi x}{48} =\pi + \frac{5 \pi}{12} = \frac{17}{12} \pi$

x = 48 * 17/12 = 68 minutes = 1 hour and 8 minutes

The results beginning at 8:00 a.m

So, the maximum will occurs at 9:08 a.m

The minimum of f(x) will be at $cos(\frac{\pi x}{48} -\frac{5 \pi}{12}) = 1$

And f(x) = -11 * 1 + 28 = -11 + 28 = 17

$cos(\frac{\pi x}{48} -\frac{5 \pi}{12}) = 1$

$\frac{\pi x}{48} -\frac{5 \pi}{12}=0$

$\frac{\pi x}{48} =\frac{5 \pi}{12}$

x = 48*5/12 = 20 minutes

The results beginning at 8:00 a.m

So, the minimum will occurs at 8:20 a.m

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